S3 Maths Scribe-post Blog

At the start of the lesson our aiims were:
1. To become confident about using Pythagoras’s technique.
2. To Learn how to find the missing shorter side.
ok so u all saw sorrel’s amazing post on pythagoras’ theorem. i will just add a tiny bit more. Yesterday in maths mr jones taught us how to find a SHORT side of a right angled triangle.
It’s pretty much the same as before except, you TAKE AWAY the squere of the non-hypotenuse side from the squere of the hypotenuse.

EXAMPLE

A ( hypotenuse) = 40cm

B = 20cm

C = x

so we would do this :

40 sq = 20 sq + x sq
so x sq = 40 sq - 20 sq
= 1600 (40 times 40) - 400 (20 times 20)
=1200
so x sq = 1200
so x = √1200
= 34.64 (approx)

Conclusion

So x, one of the two sides that isn’t the hipotonuse meaasures 34.64 centimetres.

ps I nomonate Stuart !!